Removing elements from an array in C

I just have a simple question about arrays in C:

What is the best way to remove elements from an array and in the process make the array smaller.

ie: the array is n size, then I take elements out of the array and then the array grows smaller by the amount that I removed it from.

basically I’m treating the array like a deck of cards and once I take a card off the top of the deck it shouldn’t be there anymore.

EDIT: I’m going to drive myself crazy before the end of the day, thanks for all the help I’m trying the value swapping thing but it’s not working right.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

enum faces { Ace = 0, Jack = 10, Queen, King };
char *facecheck(int d); 
int draw(int deck, int i); 

int main() { 
    int deck[52], i, n;
    char suits[4][9] = {
        "Hearts",
        "Diamonds",
        "Clubs",
        "Spades"
    };

    n = 0;

    for (i = 0; i < 52; i++) {
        deck[i] = n;
        n++;
    };

    for (i = 0; i < 52; i++) {       
        if (i % 13 == 0 || i % 13 == 10 || i % 13 == 11 || i % 13 == 12)
            printf("%s ", facecheck(i % 13));
        else
            printf("%d ", i % 13 + 1);
        printf("of %s \n", suits[i / 13]);
    }

    draw(deck, i);

    return 0; 
}  

char *facecheck(int d) {
    static char *face[] = {
        "Ace",
        "Jack",
        "Queen",
        "King"
    };

    if (d == Ace)
        return face[0];
    else {
        if (d == Jack) 
            return face[1];
        else {
            if (d == Queen)
                return face[2];
            else { 
                if (d == King)
                    return face[3];
            }
        }
    } 
}

int draw(int deck, int i) { 
    int hand[5], j, temp[j];

    for (i = 0; i < 52; i++) {
        j = i
    }; 

    for (i = 0; i < 5; i++) {
        deck[i] = hand[]; 
        printf("A card has been drawn \n");
        deck[i] = temp[j - 1];
        temp[j] = deck[i];
    };
      
    return deck;
}

You need to sign in to view this answers

Related Post