Printing a negative _BitInt in C23

If I have the following code:

_BitInt(6) c = -20;
printf("Valore di _BitInt(6) c: %d\n", c); 

The printf gives as value 236 and not -20

I noticed that to print the correct value I should write the following code instead using the cast to int operator.

printf("Valore di _BitInt(6) c: %d\n", (int)c);

What is the explanation?

Maybe printf without (int)c makes a wrong conversion of c into an unsigned 8 bit int?

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